X^2+100x=300000

Solution for X^2+100x=300000 equation:

X^2+100X=300000

We move all terms to the left:

X^2+100X-(300000)=0

a = 1; b = 100; c = -300000;
Δ = b2-4ac
Δ = 1002-4·1·(-300000)
Δ = 1210000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1210000}=1100$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-1100}{2*1}=\frac{-1200}{2}
=-600
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+1100}{2*1}=\frac{1000}{2}
=500
$